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Q.
An aqueous solution of $98 \%( w / w ) H _{2} SO _{4}$ has density of $1.02\, g / cc$. The Molality of the solution is
TS EAMCET 2020
Solution:
$\because$ Volume $=\frac{\text { Mass }( m )}{\text { Density }(d)}$
$=\frac{100}{1.02}=98.039 mL$
$\therefore \quad$ Molarity $=\frac{9.8 \times 1000}{98 \times 98.04}=1.01$
Which is close to $1.1$.