An ammeter reads upto 1A. Its internal resistance is 0.81 Ω . To increase the range to 10 A, the value of the required shunt is

Question

An ammeter reads upto 1A. Its internal resistance is 0.81 Ω . To increase the range to 10 A, the value of the required shunt is (A) 0.09 Ω (B) 0.03 Ω (C) 0.3 Ω (D) 0.9 Ω

Tardigrade Admin · Accepted Answer

Shunt S=(GI/I-Ig) =(0.81×1/10-1)=(0.81/9)Ω=0.09 Ω

Q. An ammeter reads upto $1 A$ . Its internal resistance is $0.81 Ω$ . To increase the range to $10 A$ , the value of the required shunt is

$0.09 Ω$

$0.03 Ω$

$0.3 Ω$

$0.9 Ω$

Shunt $S = \frac{G I}{I - I _{g}}$
$= \frac{0.81 \times 1}{10 - 1} = \frac{0.81}{9} Ω = 0.09 Ω$

Q. An ammeter reads upto 1A. Its internal resistance is 0.81Ω . To increase the range to 10A, the value of the required shunt is

0.09Ω

0.03Ω

0.3Ω

0.9Ω