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  4. An ammeter reads upto 1A. Its internal resistance is 0.81 Ω . To increase the range to 10 A, the value of the required shunt is

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Q. An ammeter reads upto $1A$. Its internal resistance is $0.81\, \Omega$ . To increase the range to $10\, A$, the value of the required shunt is

VITEEEVITEEE 2011

Solution:

Shunt $S=\frac{GI}{I-I_{g}}$
$=\frac{0.81\times1}{10-1}=\frac{0.81}{9}\Omega=0.09\,\Omega$