An α -particle is accelerated through a potential difference of 200 V. The increase in its kinetic energy is

Question

An α -particle is accelerated through a potential difference of 200 V. The increase in its kinetic energy is (A) 100 eV (B) 200 eV (C) 400 eV (D) 800 eV

Tardigrade Admin · Accepted Answer

K E=Q V ⇒ K E =(2 e) 200 V =400 eV

Q. An $α$ -particle is accelerated through a potential difference of $200 V$ . The increase in its kinetic energy is

100 eV

200 eV

400 eV

800 eV

$K E = Q V \Rightarrow K E$
$= (2 e) 200 V = 400 e V$

Q. An α -particle is accelerated through a potential difference of 200V. The increase in its kinetic energy is

100 eV

200 eV

400 eV

800 eV

KE=QV⇒KE =(2e)200V=400eV

Q. An $α$ -particle is accelerated through a potential difference of $200 V$ . The increase in its kinetic energy is

$K E = Q V \Rightarrow K E$
$= (2 e) 200 V = 400 e V$