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Physics
An α -particle is accelerated through a potential difference of 200 V. The increase in its kinetic energy is
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Q. An $\alpha$ -particle is accelerated through a potential difference of $200\, V$. The increase in its kinetic energy is
Electrostatic Potential and Capacitance
A
100 eV
15%
B
200 eV
29%
C
400 eV
47%
D
800 eV
9%
Solution:
$K E=Q V \Rightarrow K E$
$=(2 e) 200\, V =400\, eV$