1. Tardigrade
  2. Question
  3. Chemistry
  4. An alkene (.A.) on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane (.B.) . (.B.) is the lowest alkane which in pure form can not be prepared by standard Wurtz method. (.A.) is

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Q. An alkene $\left(\right.A\left.\right)$ on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane $\left(\right.B\left.\right)$ . $\left(\right.B\left.\right)$ is the lowest alkane which in pure form can not be prepared by standard Wurtz method. $\left(\right.A\left.\right)$ is

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Solution:

Simplest alkane which cannot be prepared by wurtz reaction is propane. So the alkene must be unsymmetrical having six carbon, which can give two different carbonyl each contain three carbons.
Solution