An alkane C 6 H 14( X ) can be obtained by reduction of five different alkyl halides C 6 H 13 Cl (only structural isomers) with Zn - CH 3 COOH. The IUPAC name of X satisfying above condition is

Question

An alkane C 6 H 14( X ) can be obtained by reduction of five different alkyl halides C 6 H 13 Cl (only structural isomers) with Zn - CH 3 COOH. The IUPAC name of X satisfying above condition is (A) hexane (B) 2-methyl pentane (C) 2,3 -dimethyl butane (D) 2,2 -dimethyl butane

Tardigrade Admin · Accepted Answer

2-methyl pentane has five types of hydrogen therefore, it can be obtained by reduction of five different halides as: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/97cd0c30f3442f2e964bd48627dcde6b-.png" /> All of the above chloroalkanes, an reduction with Zn - CH 3 COOH would give the same 2 -methyl pentane.

Q. An alkane $C_{6} H_{14} (X)$ can be obtained by reduction of five different alkyl halides $C_{6} H_{13} Cl$ (only structural isomers) with $Z n - C H_{3} COO H$ . The IUPAC name of $X$ satisfying above condition is

hexane

2-methyl pentane

2,3 -dimethyl butane

2,2 -dimethyl butane

2-methyl pentane has five types of hydrogen therefore, it can be obtained by reduction of five different halides as:

All of the above chloroalkanes, an reduction with $Z n - C H_{3} COO H$ would give the same $2$ -methyl pentane.

Q. An alkane C6​H14​(X) can be obtained by reduction of five different alkyl halides C6​H13​Cl (only structural isomers) with Zn−CH3​COOH. The IUPAC name of X satisfying above condition is