Question

An alkane $C _{6} H _{14}( X )$ can be obtained by reduction of five different alkyl halides $C _{6} H _{13} Cl$ (only structural isomers) with $Zn - CH _{3} COOH$. The IUPAC name of $X$ satisfying above condition is

• A. hexane
• B. 2-methyl pentane
• C. 2,3 -dimethyl butane
• D. 2,2 -dimethyl butane

Answer 1

Answer: (B)

2-methyl pentane has five types of hydrogen therefore, it can be obtained by reduction of five different halides as:



All of the above chloroalkanes, an reduction with $Zn - CH _{3} COOH$ would give the same $2 $-methyl pentane.