An alkaloid contains 17.28 % of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is

Question

An alkaloid contains 17.28 % of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is (A) five (B) four (C) three (D) two

Tardigrade Admin · Accepted Answer

Amount of nitrogen present in one mole of alkaloid i.e., in 162 g =(162×17.28/100) ∴ No. of nitrogen atoms per molecule =(162×17.28/100×14) =2 (approx)

Q. An alkaloid contains 17.28 % of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is

five

four

three

two

Amount of nitrogen present in one mole of alkaloid
i.e., in $162 g = \frac{162 \times 17.28}{100}$
$∴$ No. of nitrogen atoms per molecule
$= \frac{162 \times 17.28}{100 \times 14}$
$= 2$ (approx)

Q. An alkaloid contains 17.28 % of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is

five

four

three

two

Amount of nitrogen present in one mole of alkaloid i.e., in 162g=100162×17.28​ ∴ No. of nitrogen atoms per molecule =100×14162×17.28​ =2 (approx)

Amount of nitrogen present in one mole of alkaloid
i.e., in $162 g = \frac{162 \times 17.28}{100}$
$∴$ No. of nitrogen atoms per molecule
$= \frac{162 \times 17.28}{100 \times 14}$
$= 2$ (approx)