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Q.
An alkaloid contains 17.28 % of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is
Some Basic Concepts of Chemistry
Solution:
Amount of nitrogen present in one mole of alkaloid
i.e., in $162 \,g =\frac{162\times17.28}{100}$
$\therefore $ No. of nitrogen atoms per molecule
$=\frac{162\times17.28}{100\times14}$
$=2$ (approx)