An alkali metal hydride (NaH) reacts with diborane in A to give a tetrahedral compound B which is extensively used as reducing agent in organic synthesis. The compounds A and B respectively are

Question

An alkali metal hydride (NaH) reacts with diborane in A to give a tetrahedral compound B which is extensively used as reducing agent in organic synthesis. The compounds A and B respectively are (A) C2H6 and C2H5Na (B) CH3COCH3 and B3N3H6 (C) C6H6 and NaBH4 (D) (C2H5)2O and NaBH4

Tardigrade Admin · Accepted Answer

Sodium hydride NaH reacts with diborane in diethylether to give tetrahydridoborates, i.e. sodium borohydride which is used as reducing agent in organic synthesis.

Sodmm hydnde 2 N a H + Diboran B_{2} H_{6} ether Diethyl A Sodium borohydride B 2 N a^{+} [B H_{4}]^{-}]

A=diethyl ether

(C_{2} H_{5})_{2} O

B= Sodium borohydride

N a B H_{4}

Q. An alkali metal hydride $(N a H)$ reacts with diborane in $A$ to give a tetrahedral compound $B$ which is extensively used as reducing agent in organic synthesis. The compounds $A$ and $B$ respectively are

$C_{2} H_{6}$ and $C_{2} H_{5} N a$

$C H_{3} COC H_{3}$ and $B_{3} N_{3} H_{6}$

$C_{6} H_{6}$ and $N a B H_{4}$

$(C_{2} H_{5})_{2} O$ and $N a B H_{4}$

Q. An alkali metal hydride (NaH) reacts with diborane in A to give a tetrahedral compound B which is extensively used as reducing agent in organic synthesis. The compounds A and B respectively are

C2​H6​ and C2​H5​Na

CH3​COCH3​ and B3​N3​H6​

C6​H6​ and NaBH4​

(C2​H5​)2​O and NaBH4​

Q. An alkali metal hydride $(N a H)$ reacts with diborane in $A$ to give a tetrahedral compound $B$ which is extensively used as reducing agent in organic synthesis. The compounds $A$ and $B$ respectively are

$C_{2} H_{6}$ and $C_{2} H_{5} N a$

$C H_{3} COC H_{3}$ and $B_{3} N_{3} H_{6}$

$C_{6} H_{6}$ and $N a B H_{4}$

$(C_{2} H_{5})_{2} O$ and $N a B H_{4}$