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  4. An alkali metal hydride (NaH) reacts with diborane in A to give a tetrahedral compound B which is extensively used as reducing agent in organic synthesis. The compounds A and B respectively are

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Q. An alkali metal hydride $(NaH)$ reacts with diborane in $A$ to give a tetrahedral compound $B$ which is extensively used as reducing agent in organic synthesis. The compounds $A$ and $B$ respectively are

KCETKCET 2015The p-Block Elements

Solution:

Sodium hydride NaH reacts with diborane in diethylether to give tetrahydridoborates, i.e. sodium borohydride which is used as reducing agent in organic synthesis.

$\underset{\text{Sodmm hydnde }}{{2NaH}} +\underset{\text{Diboran}}{{B_2H_6}} \xrightarrow[\text{Diethyl}]{\text{ether}} A \underset{\text{Sodium borohydride B}}{{2Na^+[BH_4]^-]}}$

A=diethyl ether $\left( C _{2} H _{5}\right)_{2} O$ B= Sodium borohydride $NaBH _{4}$