An air of length 14.4 cm column is trapped by a mercury column of length 15.2 cm as shown in figure. If the tube is now kept vertically with its open end up. Find the length of air column.

Question

An air of length 14.4 cm column is trapped by a mercury column of length 15.2 cm as shown in figure. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/08c7704405c9713ae8b5238ca1c7959a-.png" /> If the tube is now kept vertically with its open end up. Find the length of air column. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

From Boyle's Law P1 V1=P2 V2 P1 × A × l1=P2 A × l2 where A= cross sectional area 76 × 14.4=(76+15.2) × l2 l2=12 cm

Q. An air of length $14.4 c m$ column is trapped by a mercury column of length $15.2 c m$ as shown in figure.

If the tube is now kept vertically with its open end up. Find the length of air column.

From Boyle's Law
$P_{1} V_{1} = P_{2} V_{2}$
$P_{1} \times A \times l_{1} = P_{2} A \times l_{2}$
where $A =$ cross sectional area
$76 \times 14.4 = (76 + 15.2) \times l_{2}$
$l_{2} = 12 c m$

Q. An air of length 14.4cm column is trapped by a mercury column of length 15.2cm as shown in figure. If the tube is now kept vertically with its open end up. Find the length of air column.

From Boyle's Law P1​V1​=P2​V2​ P1​×A×l1​=P2​A×l2​ where A= cross sectional area 76×14.4=(76+15.2)×l2​ l2​=12cm

Q. An air of length $14.4 c m$ column is trapped by a mercury column of length $15.2 c m$ as shown in figure.

If the tube is now kept vertically with its open end up. Find the length of air column.

From Boyle's Law
$P_{1} V_{1} = P_{2} V_{2}$
$P_{1} \times A \times l_{1} = P_{2} A \times l_{2}$
where $A =$ cross sectional area
$76 \times 14.4 = (76 + 15.2) \times l_{2}$
$l_{2} = 12 c m$