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  4. An air of length 14.4 cm column is trapped by a mercury column of length 15.2 cm as shown in figure. <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/chemistry/08c7704405c9713ae8b5238ca1c7959a-.png /> If the tube is now kept vertically with its open end up. Find the length of air column.

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Q. An air of length $14.4\, cm$ column is trapped by a mercury column of length $15.2 \,cm$ as shown in figure.
image
If the tube is now kept vertically with its open end up. Find the length of air column.

States of Matter

Solution:

From Boyle's Law
$P_{1} V_{1}=P_{2} V_{2}$
$P_{1} \times A \times l_{1}=P_{2} A \times l_{2}$
where $A=$ cross sectional area
$76 \times 14.4=(76+15.2) \times l_{2} $
$l_{2}=12 \,cm$