An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is

Question

An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is (A) 8 (B) 10 (C) 12 (D) 16

Tardigrade Admin · Accepted Answer

dap = (dac/μ) ( 5+ 3 ) = (dac/1.5) dac = (5+3) (1.5) = 12 cm

Q. An air bubble in a glass slab with refractive index $1.5$ (near normal incidence) is $5 c m$ deep when viewed from one surface and $3 c m$ deep when viewed from the opposite face. The thickness (in cm) of the slab is

8

10

12

16

$d_{a p} = \frac{d _{a c}}{μ}$
$(5 + 3) = \frac{d _{a c}}{1.5}$
$d_{a c} = (5 + 3) (1.5) = 12 c m$

Q. An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 5cm deep when viewed from one surface and 3cm deep when viewed from the opposite face. The thickness (in cm) of the slab is

8

10

12

16

dap​=μdac​​ (5+3)=1.5dac​​ dac​=(5+3)(1.5)=12cm

Q. An air bubble in a glass slab with refractive index $1.5$ (near normal incidence) is $5 c m$ deep when viewed from one surface and $3 c m$ deep when viewed from the opposite face. The thickness (in cm) of the slab is

$d_{a p} = \frac{d _{a c}}{μ}$
$(5 + 3) = \frac{d _{a c}}{1.5}$
$d_{a c} = (5 + 3) (1.5) = 12 c m$