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Q. An air bubble in a glass slab with refractive index $1.5$ (near normal incidence) is $5\,cm$ deep when viewed from one surface and $3\,cm$ deep when viewed from the opposite face. The thickness (in cm) of the slab is

NEETNEET 2016Ray Optics and Optical Instruments

Solution:

$d_{ap} = \frac{d_{ac}}{\mu} $
$ \left( 5+ 3 \right) = \frac{d_{ac}}{1.5}$
$ d_{ac} = \left(5+3\right) \left(1.5\right) = 12 cm $

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