An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

Question

An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (A) 1200 m (B) 0.33 km (C) 33.3 km (D) 3.33 km

Tardigrade Admin · Accepted Answer

From equation of motion where we have h =(1/2) gt 2 ⇒ t =√(2 × 1960/9.8)=20 s ∴ s = AB = ut =600 × (20/60 × 60)=3.33 km

Q. An aeroplane is flying horizontally with a velocity of $600 km / h$ and at a height of $1960 m$ . When it is vertically above a point $A$ on the ground, a bomb is released from it. The bomb strikes the ground at point $B$ . The distance $A B$ is

1200 m

0.33 km

33.3 km

3.33 km

From equation of motion where we have
$h = \frac{1}{2} g t^{2}$
$\Rightarrow t = \frac{2 \times 1960}{9.8} = 20 s$
$∴ s = A B = u t = 600 \times \frac{20}{60 \times 60} = 3.33 km$

Q. An aeroplane is flying horizontally with a velocity of 600km/h and at a height of 1960m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is