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Q. An aeroplane is flying horizontally with a velocity of $600\, km/h$ and at a height of $1960\, m$. When it is vertically above a point $A$ on the ground, a bomb is released from it. The bomb strikes the ground at point $B$. The distance $AB$ is

Motion in a Plane

Solution:

From equation of motion where we have
$h =\frac{1}{2} gt ^{2}$
$\Rightarrow \quad t =\sqrt{\frac{2 \times 1960}{9.8}}=20 s$
$\therefore s = AB = ut =600 \times \frac{20}{60 \times 60}=3.33\, km$