An aeroplane is flying horizontally with a velocity of 216 kmh- 1 and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance) (given g=9.8 ms- 2 )

Question

An aeroplane is flying horizontally with a velocity of 216 kmh- 1 and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance) (given g=9.8 ms- 2 ) (A) 1200 m (B) 0.33 km (C) 3.33 km (D) 33 km

Tardigrade Admin · Accepted Answer

The horizontal velocity of the aeroplane, in m/s u=(216 × 1000/60 × 6 0)=60ms- 1 Time of flight, T=√(2 h/g)=√(2 × 1960/9.8)=20s Horizontal range, AB=uT =60× 20=1200m

Q. An aeroplane is flying horizontally with a velocity of $216 km h^{- 1}$ and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance) (given $g = 9.8 m s^{- 2}$ )

1200 m

0.33 km

3.33 km

33 km

The horizontal velocity of the aeroplane, in m/s
$u = \frac{216 \times 1000}{60 \times 60} = 60 m s^{- 1}$
Time of flight, $T = \frac{2 h}{g} = \frac{2 \times 1960}{9.8} = 20 s$
Horizontal range, $A B = u T$ $= 60 \times 20 = 1200 m$

Q. An aeroplane is flying horizontally with a velocity of 216kmh−1 and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance) (given g=9.8ms−2 )