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Q. An aeroplane is flying horizontally with a velocity of $216 \, kmh^{- 1}$ and at a height of 1960 m. When it is vertically above a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is (ignoring air resistance) (given $g=9.8 \, ms^{- 2}$ )

NTA AbhyasNTA Abhyas 2022

Solution:

The horizontal velocity of the aeroplane, in m/s
$u=\frac{216 \times 1000}{60 \times 6 0}=60ms^{- 1}$
Time of flight, $T=\sqrt{\frac{2 h}{g}}=\sqrt{\frac{2 \times 1960}{9.8}}=20s$
Horizontal range, $AB=uT$ $=60\times 20=1200m$