An A.C voltage E=200 sin 300 t is applied across a series combination of R =10 Ω and L =800 mH. Calculate the power factor of the circuit.

Question

An A.C voltage E=200 sin 300 t is applied across a series combination of R =10 Ω and L =800 mH. Calculate the power factor of the circuit. (A) 0.0315 (B) 0.416 (C) 0.0416 (D) 4.17

Tardigrade Admin · Accepted Answer

XL=ω L=300 × 800 × 10-3=240 Ω Z=√R2+XL2=√(10)2+(240)2=240.2 Ω Power factor, cos φ=(R/Z)=(10/240.2)=0.0416

Q. An A.C voltage $E = 200 sin 300$ t is applied across a series combination of $R = 10Ω$ and $L = 800 m H$ . Calculate the power factor of the circuit.

0.0315

0.416

0.0416

4.17

$X_{L} = ω L = 300 \times 800 \times 1 0^{- 3} = 240Ω$
$Z = R^{2} + X_{L}^{2} = (10)^{2} + (240)^{2} = 240.2Ω$
Power factor, $cos ϕ = \frac{R}{Z} = \frac{10}{240.2} = 0.0416$

Q. An A.C voltage E=200sin300 t is applied across a series combination of R=10Ω and L=800mH. Calculate the power factor of the circuit.