Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with NaNO2 in dil. HCl followed by addition to an alkaline solution of β - naphthol is

Question

Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with NaNO2 in dil. HCl followed by addition to an alkaline solution of β - naphthol is (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

As we know, benzenediazonium salt forms brilliant coloured dye with

β

-naphthol, the compound under consideration must be p-toluidine (c) as it is a primary aromatic amine. Primary aromatic amine, on treatment with

N a N O_{2}

in dil. HCI forms the corresponding diazonium chloride salt.
Solution

Q. Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with NaNO2​ in dil. HCl followed by addition to an alkaline solution of β− naphthol is

As we know, benzenediazonium salt forms brilliant coloured dye with β -naphthol, the compound under consideration must be p-toluidine (c) as it is a primary aromatic amine. Primary aromatic amine, on treatment with NaNO2​ in dil. HCI forms the corresponding diazonium chloride salt.

Q. Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with $N a N O_{2}$ in dil. $H Cl$ followed by addition to an alkaline solution of $β -$ naphthol is

As we know, benzenediazonium salt forms brilliant coloured dye with $β$ -naphthol, the compound under consideration must be p-toluidine (c) as it is a primary aromatic amine. Primary aromatic amine, on treatment with $N a N O_{2}$ in dil. HCI forms the corresponding diazonium chloride salt.