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  4. Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with NaNO2 in dil. HCl followed by addition to an alkaline solution of β - naphthol is

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Q. Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with $NaNO_{2}$ in dil. $HCl$ followed by addition to an alkaline solution of $\beta -$ naphthol is

NTA AbhyasNTA Abhyas 2022

Solution:

As we know, benzenediazonium salt forms brilliant coloured dye with $\beta $ -naphthol, the compound under consideration must be p-toluidine (c) as it is a primary aromatic amine. Primary aromatic amine, on treatment with $NaNO_{2}$ in dil. HCI forms the corresponding diazonium chloride salt.
Solution