Q. Among the following, which one equals minimum excitation potential of Bohr's first orbit in hydrogen atom ?

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A

$13.6 V$

B

$3.4 V$

C

$10.2 V$

D

$3.6 V$

Solution:

We know, Excitation energy = $e$ (Excitation potential) ....eq $1$
Excitation energy of Bohr's first orbit in hydrogen atom is minimum when transition of electron is from $n = 1$ to $n = 2$ .
Minimum Excitation energy in hydrogen atom, $(E_{min})$ $= E_{2} - E_{1}$
$E_{min} = - 3.4 - (- 13.6) e V$
$E_{min} = 10.2 e V$
From eq $1$
So, minimum Excitation potential $= \frac{E _{min}}{e}$
Minimum excitation potential of Bohr's first orbit $= 10.2 V$