Q. Among the following, which one equals minimum excitation potential of Bohr's first orbit in hydrogen atom ?
NTA AbhyasNTA Abhyas 2020
Solution:
We know, Excitation energy = $e$ (Excitation potential) ....eq $1$
Excitation energy of Bohr's first orbit in hydrogen atom is minimum when transition of electron is from $n=1$ to $n=2$ .
Minimum Excitation energy in hydrogen atom, $\left(\right.E_{m i n}\left.\right)$ $=E_{2}-E_{1}$
$E_{m i n}=-3.4-\left(\right.-13.6\left.\right)eV$
$E_{m i n}=10.2eV$
From eq $1$
So, minimum Excitation potential $=\frac{E_{m i n}}{e}$
Minimum excitation potential of Bohr's first orbit $=10.2V$
Excitation energy of Bohr's first orbit in hydrogen atom is minimum when transition of electron is from $n=1$ to $n=2$ .
Minimum Excitation energy in hydrogen atom, $\left(\right.E_{m i n}\left.\right)$ $=E_{2}-E_{1}$
$E_{m i n}=-3.4-\left(\right.-13.6\left.\right)eV$
$E_{m i n}=10.2eV$
From eq $1$
So, minimum Excitation potential $=\frac{E_{m i n}}{e}$
Minimum excitation potential of Bohr's first orbit $=10.2V$