Question

Among the compounds, $B{F}_3,NC{l}_3,H_{2}S,S{F}_4$ and $BeC{l}_2$, identify the ones in which the central atom has the same type of hybridisation

• A. $B{F}_3$ and $NC{l}_3$
• B. $H_{2}S$ and $BeC{l}_2$
• C. $B{F}_3,NC{l}_3$ and $H_{2}S$
• D. $NC{l}_3$ and $H_{2}S$

Answer 1

Answer: (D)

In $NC{l}_3$ and $H_{2}S$ the central atom of both ($N$ and $S$) are in $s{p}^3$ hybridization state

while in $B{F}_3$ and $NC{l}_3$ central atoms are in $s{p}^2$ and $s{p}^3$ hybridization respectively. In $H_{2}S$ and $BeC{l}_2$ central atom are in $s{p}^3$ and $s{p}^2$ hybridization In $B{F}_3$, $NC{l}_3$ and $H_{2}S$ central atom are in $s{p}^2,s{p}^3$ and $s{p}^3$ hybridization and in $NC{l}_3$ and $H_{2}S$ the central atom are in $s{p}^3$ and $s{p}^3$ hybridization.