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Q. Among the compounds, $BF_3, NCl_3, H_2S , SF_4$ and $BeCl_2$, identify the ones in which the central atom has the same type of hybridisation

Chemical Bonding and Molecular Structure

Solution:

In $NCl_3$ and $H_2S$ the central atom of both ($N$ and $S$) are in $sp^3$ hybridization state
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while in $BF_3$ and $NCl_3$ central atoms are in $sp^2$ and $sp^3$ hybridization respectively. In $H_2S$ and $BeCl_2$ central atom are in $sp^3$ and $sp^2$ hybridization In $BF_3$, $NCl_3$ and $H_2S$ central atom are in $sp^2, sp^3$ and $sp^3$ hybridization and in $NCl_3$ and $H_2S$ the central atom are in $sp^3$ and $sp^3$ hybridization.