Ammonia gas is passed into water, yielding a solution of density 0.93 g / cm 3 and containing 18.6 % NH 3 by weight. The mass of NH 3 per cc of the solution is

Question

Ammonia gas is passed into water, yielding a solution of density 0.93 g / cm 3 and containing 18.6 % NH 3 by weight. The mass of NH 3 per cc of the solution is (A) 0.17 g / cm 3 (B) 0.34 g / cm 3 (C) 0.51 g / cm 3 (D) 0.68 g / cm 3

Tardigrade Admin · Accepted Answer

Molarity of NH 3 solution =(18.6 × 0.93 × 10/17)=10.17 M Strength ( g / L )= molarity × mol. mass =10.17 × 17=172.9 g / L i.e., 1000 mL of solution contain NH 3=172.9 g 1 mL or 1 cm 3 of solution contain NH 3=(172.9/1000)=0.172 g ≈ 0.17 g

Q. Ammonia gas is passed into water, yielding a solution of density $0.93 g / c m^{3}$ and containing $18.6% N H_{3}$ by weight. The mass of $N H_{3}$ per cc of the solution is

$0.17 g / c m^{3}$

$0.34 g / c m^{3}$

$0.51 g / c m^{3}$

$0.68 g / c m^{3}$

Q. Ammonia gas is passed into water, yielding a solution of density 0.93g/cm3 and containing 18.6%NH3​ by weight. The mass of NH3​ per cc of the solution is

0.17g/cm3

0.34g/cm3

0.51g/cm3

0.68g/cm3

Molarity of NH3​ solution =1718.6×0.93×10​=10.17M Strength (g/L)= molarity × mol. mass =10.17×17=172.9g/L i.e., 1000mL of solution contain NH3​=172.9g 1mL or 1cm3 of solution contain NH3​=1000172.9​=0.172g≈0.17g

Q. Ammonia gas is passed into water, yielding a solution of density $0.93 g / c m^{3}$ and containing $18.6% N H_{3}$ by weight. The mass of $N H_{3}$ per cc of the solution is

$0.17 g / c m^{3}$

$0.34 g / c m^{3}$

$0.51 g / c m^{3}$

$0.68 g / c m^{3}$