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Q. Ammonia gas is passed into water, yielding a solution of density $0.93\, g / cm ^{3}$ and containing $18.6 \% NH _{3}$ by weight. The mass of $NH _{3}$ per cc of the solution is

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Solution:

Molarity of $NH _{3}$ solution $=\frac{18.6 \times 0.93 \times 10}{17}=10.17\, M$ Strength $( g / L )=$ molarity $\times$ mol. mass
$=10.17 \times 17=172.9\, g / L$
i.e., $1000\, mL$ of solution contain $NH _{3}=172.9\, g$
$1\, mL$ or $1\, cm ^{3}$ of solution contain
$NH _{3}=\frac{172.9}{1000}=0.172\, g \approx 0.17\, g$