Alkene R-CH=CH2 reacts with B2H6 to give a product. The oxidation of product by alkaline hydrogen peroxide to form

Question

Alkene R-CH=CH2 reacts with B2H6 to give a product. The oxidation of product by alkaline hydrogen peroxide to form (A)  R- underset beginsmallmatrix || O endsmallmatrix mathopC -CH3  (B)  R- underset beginsmallmatrix | OH endsmallmatrix mathopC - underset beginsmallmatrix | OH endsmallmatrix mathopCH2  (C)  R-CH2-CHO  (D)  R-CH2-CH2-OH

Tardigrade Admin · Accepted Answer

undersetalkene mathop3R-CH=CH2 + undersetdiborane mathopB2H6 xrightarrow[] (R-CH2-CH2)3B R-CH2-CH2OH

Q. Alkene $R - C H = C H_{2}$ reacts with $B_{2} H_{6}$ to give a product. The oxidation of product by alkaline hydrogen peroxide to form

$R - ∣∣ O C - C H_{3}$

$R - ∣ O H C - ∣ O H C H_{2}$

$R - C H_{2} - C H O$

$R - C H_{2} - C H_{2} - O H$

$a l k e n e 3 R - C H = C H_{2} + d ib or an e B_{2} H_{6}$ $(R - C H_{2} - C H_{2})_{3} B$
$R - C H_{2} - C H_{2} O H$

Q. Alkene R−CH=CH2​ reacts with B2​H6​ to give a product. The oxidation of product by alkaline hydrogen peroxide to form

R−∣∣O​C​−CH3​

R−∣OH​C​−∣OH​CH2​​

R−CH2​−CHO

R−CH2​−CH2​−OH