Question

Alkene $ R-CH=C{{H}_{2}} $ reacts with $ {{B}_{2}}{{H}_{6}} $ to give a product. The oxidation of product by alkaline hydrogen peroxide to form

• A. $ R-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}} $
• B. $ R-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\, $
• C. $ R-C{{H}_{2}}-CHO $
• D. $ R-C{{H}_{2}}-C{{H}_{2}}-OH $

Answer 1

Answer: (D)

$ \underset{alkene}{\mathop{3R-CH=C{{H}_{2}}}}\,+\underset{diborane}{\mathop{{{B}_{2}}{{H}_{6}}}}\,\xrightarrow[{}]{{}} $ $ {{(R-C{{H}_{2}}-C{{H}_{2}})}_{3}}B $
$ R-C{{H}_{2}}-C{{H}_{2}}OH $