AlCl 3 achieves stability by forming a dimer. In trivalent state the compound is hydrolysed in water. AlCl3 in acidified aqueous solution forms

Question

AlCl 3 achieves stability by forming a dimer. In trivalent state the compound is hydrolysed in water. AlCl3 in acidified aqueous solution forms (A)  Al(OH)3+HCl (B)  [Al(H2O)6]3++3Cl- (C) AlCl3⋅2H2O (D) Al2O3+HCl

Tardigrade Admin · Accepted Answer

AlCl3 in acidified aqueous solution forms [Al(H2O)6]3+ ion. AlCl3+9H2O →[Al(H2O)6](OH)3+3H++3Cl-

Q. $A lC l_{3}$ achieves stability by forming a dimer. In trivalent state the compound is hydrolysed in water. $A lC l_{3}$ in acidified aqueous solution forms

$A l (O H)_{3} + H Cl$

$[A l (H_{2} O)_{6}]^{3 +} + 3 C l^{-}$

$A lC l_{3} \cdot 2 H_{2} O$

$A l_{2} O_{3} + H Cl$

$A lC l_{3}$ in acidified aqueous solution forms $[A l (H_{2} O)_{6}]^{3 +}$ ion.
$A lC l_{3} + 9 H_{2} O \to [A l (H_{2} O)_{6}] (O H)_{3} + 3 H^{+} + 3 C l^{-}$

Q. AlCl3​ achieves stability by forming a dimer. In trivalent state the compound is hydrolysed in water. AlCl3​ in acidified aqueous solution forms

Al(OH)3​+HCl

[Al(H2​O)6​]3++3Cl−

AlCl3​⋅2H2​O

Al2​O3​+HCl