Question

$AlCl_ 3$ achieves stability by forming a dimer. In trivalent state the compound is hydrolysed in water. $AlCl_3$ in acidified aqueous solution forms

• A. $ Al\left(OH\right)_{3}+HCl$
• B. $ \left[Al\left(H_{2}O\right)_{6}\right]^{3+}+3Cl^{-}$
• C. $AlCl_{3}\cdot2H_{2}O$
• D. $Al_{2}O_{3}+HCl$

Answer 1

Answer: (B)

$AlCl_3$ in acidified aqueous solution forms $[Al(H_2O)_6]^{3+}$ ion.
$AlCl_{3}+9H_{2}O \to\left[Al\left(H_{2}O\right)_{6}\right]\left(OH\right)_{3}+3H^{+}+3Cl^{-}$