Al 2 O 3 was leached with alkali to get X. The solution of X on passing of gas Y, forms Z . X Y and Z respectively are

Question

Al 2 O 3 was leached with alkali to get X. The solution of X on passing of gas Y, forms Z . X Y and Z respectively are (A) X = Na [ Al ( OH )4], Y = SO 2, Z = Al 2 O 3 (B) X = Na [ Al ( OH )4], Y = CO 2, Z = Al 2 O 3 ⋅ xH 2 O (C) X = Al ( OH )3, Y = CO 2, L = Al 2 O 3 (D) X = Al ( OH )3, Y = SO 2, Z = Al 2 O 3 ⋅ xH 2 O

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/6e0deae8f5649e2fbacf92640858fb3e-.png" /> So X: Na[Al(OH)4] Y: CO2 Z: Al2O3. xH2O

Q. $A l_{2} O_{3}$ was leached with alkali to get $X$ . The solution of $X$ on passing of gas $Y$ , forms $Z . X$ $Y$ and $Z$ respectively are

$X = N a [A l (O H)_{4}], Y = S O_{2}, Z = A l_{2} O_{3}$

$X = N a [A l (O H)_{4}], Y = C O_{2}, Z = A l_{2} O_{3} \cdot x H_{2} O$

$X = A l (O H)_{3}, Y = C O_{2}, L = A l_{2} O_{3}$

$X = A l (O H)_{3}, Y = S O_{2}, Z = A l_{2} O_{3} \cdot x H_{2} O$

So

$X : N a [A l (O H)_{4}]$

$Y : C O_{2}$

$Z : A l_{2} O_{3} . x H_{2} O$

Q. Al2​O3​ was leached with alkali to get X. The solution of X on passing of gas Y, forms Z.X Y and Z respectively are

X=Na[Al(OH)4​],Y=SO2​,Z=Al2​O3​

X=Na[Al(OH)4​],Y=CO2​,Z=Al2​O3​⋅xH2​O

X=Al(OH)3​,Y=CO2​,L=Al2​O3​

X=Al(OH)3​,Y=SO2​,Z=Al2​O3​⋅xH2​O