Question

$Al _{2} O _{3}$ was leached with alkali to get $X$. The solution of $X$ on passing of gas $Y$, forms $Z . X$ $Y$ and $Z$ respectively are

• A. $X = Na \left[ Al ( OH )_{4}\right], Y = SO _{2}, Z = Al _{2} O _{3}$
• B. $X = Na \left[ Al ( OH )_{4}\right], Y = CO _{2}, Z = Al _{2} O _{3} \cdot xH _{2} O$
• C. $X = Al ( OH )_{3}, Y = CO _{2}, L = Al _{2} O _{3}$
• D. $X = Al ( OH )_{3}, Y = SO _{2}, Z = Al _{2} O _{3} \cdot xH _{2} O$

Answer 1

Answer: (B)

So

$X : Na[Al(OH)_4]$

$Y : CO_2$

$Z : Al_2O_3. xH_2O$