Question

$Ag$ is electro deposited on a metallic vessel of surface area $800c{m}^2$ by passing a current of $0.2$ amp for three hours. The thickness of silver deposited is $x\times 10^{-4}cm$ (given density is $10.47g/cc$ ). The value of $x$ is
(Note: Report your answer after multiplying with $100$ and rounding up to the nearest integer value.)

Answer 1

Answer: 288

Surface area $=800c{m}^2$
$I=0.2amp$ for $t=3hr=3\times 3600sec$
Let $t$ is the thickness of $Ag$ deposited, then it will happen on the one side of plate
Volume $=A.t.=800\times tc{m}^3=800tc{m}^3$
$d_{Ag}=10.47g/cc$
$m_{Ag}=d_{Ag}.V_{Ag}=800t\times 10.47=8376t$
$m_{Ag}=Z_{Ag}.I.t=\frac{\frac{108}{1}}{96500}\times 3\times 3600\times 0.2$
$8376t=\frac{108\times 108}{965}\times \frac{2}{10}=12.087\times \frac{2}{10}$
$t=\frac{12.087}{8376}\times \frac{2}{10}$
Thickness of $Ag$ deposited in the vessel $=2.88\times 10^{-4}cm$
Final answer $=2.88\times 100=288$