Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from x=0m to x=35m is equal to

Question

Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from x=0m to x=35m is equal to <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-q4uzubfir3ppzfsy.jpg" /> (A) 50 J (B) 25 J (C) 250 J (D) 200 J

Tardigrade Admin · Accepted Answer

Work done = area under the graph =(10 × 10/2)+15× 10+(10 × 10/2)=250J

Q. Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from $x = 0 m$ to $x = 35 m$ is equal to

50 J

25 J

250 J

200 J

Work done = area under the graph $= \frac{10 \times 10}{2} + 15 \times 10 + \frac{10 \times 10}{2} = 250 J$

Q. Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from x=0m to x=35m is equal to