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  4. Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from x=0m to x=35m is equal to <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-q4uzubfir3ppzfsy.jpg />

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Q. Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from $x=0m$ to $x=35m$ is equal to
Question

NTA AbhyasNTA Abhyas 2020

Solution:

Work done = area under the graph $=\frac{10 \times 10}{2}+15\times 10+\frac{10 \times 10}{2}=250J$