Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives

Question

Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives (A) acetone (B) acetamide (C) 2-methyl-2-propanol (D) acetyl iodide

Tardigrade Admin · Accepted Answer

Correct answer is (c) 2-methyl-2-propanol

Q. Acetyl bromide reacts with excess of CH3​MgI followed by treatment with a saturated solution of NH4​Cl gives

acetone

acetamide

2-methyl-2-propanol

acetyl iodide

Correct answer is (c) 2-methyl-2-propanol

Q. Acetyl bromide reacts with excess of $C H_{3} M g I$ followed by treatment with a saturated solution of $N H_{4} Cl$ gives