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Chemistry
Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives
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Q. Acetyl bromide reacts with excess of $CH_3MgI$ followed by treatment with a saturated solution of $NH_4Cl$ gives
Haloalkanes and Haloarenes
A
acetone
100%
B
acetamide
0%
C
2-methyl-2-propanol
0%
D
acetyl iodide
0%
Solution:
Correct answer is (c) 2-methyl-2-propanol