Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?

Question

Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine? (A) NaOH-Br2 (B) Sodalime (C) Hot conc. H2SO4 (D) PCl5

Tardigrade Admin · Accepted Answer

The reagent which can convert - CONH 2 group into - NH 2 group is used for this reaction. Among the given reagents only NaOH / Br 2 converts - CONH 2 group to - NH 2 group, thus it is used for converting acetamide to methyl amine. This reaction is called Hoffman bromide reaction. CH 3 CONH 2+ NaOH + Br 2 → CH 3 NH 2+ NaBr + Na 2 CO 3+ H 2 O The reagent which can convert - CONH 2 group into - NH 2 group is used for this reaction. Among the given reagents only NaOH / Br 2 converts - CONH 2 group to - NH 2 group, thus it is used for converting acetamide to methyl amine. This reaction is called Hoffman bromide reaction. CH 3 CONH 2+ NaOH + Br 2 → CH 3 NH 2+ NaBr + Na 2 CO 3+ H 2 O

Q. Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?

$N a O H - B r_{2}$

Sodalime

Hot conc. $H_{2} S O_{4}$

$PC l_{5}$

Q. Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?

NaOH−Br2​

Sodalime

Hot conc. H2​SO4​

PCl5​

$N a O H - B r_{2}$

Hot conc. $H_{2} S O_{4}$

$PC l_{5}$