Acetamide and ethylamine can be distinguished by reacting with

Question

Acetamide and ethylamine can be distinguished by reacting with (A) aqueous HCl and heat (B) aqueous NaOH and heat (C) acidified KMnO4  (D) bromine water

Tardigrade Admin · Accepted Answer

Acetamide and ethylamine can be distinguished by heating with NaOH solution when acetamide liberates NH3 but ethylamine does not. CH3CONH2 + NaOH ->[Δ]CH3COONa + NH3 CH3CH2NH2 + NaOH → No reaction

Q. Acetamide and ethylamine can be distinguished by reacting with

aqueous $H Cl$ and heat

aqueous $N a O H$ and heat

acidified $K M n O_{4}$

bromine water

Acetamide and ethylamine can be distinguished by heating with $N a O H$ solution when acetamide liberates $N H_{3}$ but ethylamine does not.
$C H_{3} CON H_{2} + N a O H Δ C H_{3} COON a + N H_{3}$
$C H_{3} C H_{2} N H_{2} + N a O H \to$ No reaction

Q. Acetamide and ethylamine can be distinguished by reacting with

aqueous HCl and heat

aqueous NaOH and heat

acidified KMnO4​

bromine water

Acetamide and ethylamine can be distinguished by heating with NaOH solution when acetamide liberates NH3​ but ethylamine does not. CH3​CONH2​+NaOHΔ​CH3​COONa+NH3​ CH3​CH2​NH2​+NaOH→ No reaction

aqueous $H Cl$ and heat

aqueous $N a O H$ and heat

acidified $K M n O_{4}$

Acetamide and ethylamine can be distinguished by heating with $N a O H$ solution when acetamide liberates $N H_{3}$ but ethylamine does not.
$C H_{3} CON H_{2} + N a O H Δ C H_{3} COON a + N H_{3}$
$C H_{3} C H_{2} N H_{2} + N a O H \to$ No reaction