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Q. Acetamide and ethylamine can be distinguished by reacting with

ManipalManipal 2010

Solution:

Acetamide and ethylamine can be distinguished by heating with $ NaOH $ solution when acetamide liberates $NH_3$ but ethylamine does not.
$ CH_3CONH_2 + NaOH \ce{->[\Delta]}CH_3COONa + NH_3$
$CH_3CH_2NH_2 + NaOH \to $ No reaction