Question

According to molecular orbital theory for $O_2{}^{+}$

• A. bond order is less than $O_2$ and $O_2^{+}$ is paramagnetic
• B. bond order is more than $O_2$ and $O_2^{+}$ is paramagnetic
• C. bond order is less than $O_2$ and $O_2^{+}$ is diamagnetic
• D. bond order is more than $O_2$ and $O_2^{+}$ is diamagnetic

Answer 1

Answer: (B)

Bond order for $O_2=2$ and for $O_2^{+}=2.5$ Both are paramagnetic $(O_2$ has 2 unpaired electrons, $O_2^{+}$ has one unpaired electron).