Question

According to molecular orbital theory for $O _{2}{ }^{+}$

• A. bond order is less than $O _{2}$ and $O _{2}^{+}$ is paramagnetic
• B. bond order is more than $O _{2}$ and $O _{2}^{+}$ is paramagnetic
• C. bond order is less than $O _{2}$ and $O _{2}^{+}$ is diamagnetic
• D. bond order is more than $O _{2}$ and $O _{2}^{+}$ is diamagnetic

Answer 1

Answer: (B)

Bond order for $O _{2}=2$ and for $O _{2}^{+}=2.5$ Both are paramagnetic $\left( O _{2}\right.$ has 2 unpaired electrons, $O _{2}^{+}$ has one unpaired electron).