According to Molecular Orbital Theory,

Question

According to Molecular Orbital Theory, (A) C 22- is expected to be diamagnetic (B) O 22+ is expected to have a longer bond length than O 2 (C) N 2+and N 2-have the same bond order (D) He 2+has the same energy as two isolated He atoms

Tardigrade Admin · Accepted Answer

arrow C 22- has 14 e -. It is expected to be diamagnetic arrow N 2+and N 2-have the same bond order 2.5.

Q. According to Molecular Orbital Theory,

$C_{2}^{2 -}$ is expected to be diamagnetic

$O_{2}^{2 +}$ is expected to have a longer bond length than $O_{2}$

$N_{2}^{+}$ and $N_{2}^{-}$ have the same bond order

$H e_{2}^{+}$ has the same energy as two isolated He atoms

$\to C_{2}^{2 -}$ has $14 e^{-}$ . It is expected to be diamagnetic
$\to N_{2}^{+}$ and $N_{2}^{-}$ have the same bond order $2.5$ .

Q. According to Molecular Orbital Theory,

C22−​ is expected to be diamagnetic

O22+​ is expected to have a longer bond length than O2​

N2+​and N2−​have the same bond order

He2+​has the same energy as two isolated He atoms

→C22−​ has 14e−. It is expected to be diamagnetic →N2+​and N2−​have the same bond order 2.5.

$C_{2}^{2 -}$ is expected to be diamagnetic

$O_{2}^{2 +}$ is expected to have a longer bond length than $O_{2}$

$N_{2}^{+}$ and $N_{2}^{-}$ have the same bond order

$H e_{2}^{+}$ has the same energy as two isolated He atoms

$\to C_{2}^{2 -}$ has $14 e^{-}$ . It is expected to be diamagnetic
$\to N_{2}^{+}$ and $N_{2}^{-}$ have the same bond order $2.5$ .