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Tardigrade
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Chemistry
According to Molecular Orbital Theory,
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Q. According to Molecular Orbital Theory,
JEE Advanced
JEE Advanced 2016
A
$C _{2}^{2-}$ is expected to be diamagnetic
B
$O _{2}^{2+}$ is expected to have a longer bond length than $O _{2}$
C
$N _{2}^{+}$and $N _{2}^{-}$have the same bond order
D
$He _{2}^{+}$has the same energy as two isolated He atoms
Solution:
$\rightarrow C _{2}^{2-}$ has $14 e ^{-}$. It is expected to be diamagnetic
$\rightarrow N _{2}^{+}$and $N _{2}^{-}$have the same bond order $2.5$.