Question

According to Charles' law (1) ${\left(\frac{dV}{dT}\right)}_p=K$ (2) ${\left(\frac{dT}{dV}\right)}_p=K$ (3) ${\left(\frac{1}{T}-\frac{V}{T^2}\right)}_p=0$ (4) $V\propto \frac{1}{T}$

• A. 1, 2 and 3 are correct
• B. 1 and 2 are correct
• C. 2 and 4 are correct
• D. 1 and 3 are correct

Answer 1

Answer: (A)

According to Charles law $V\propto t$ at constant p $V=kT$ at constant p Or ${\left(\frac{dV}{dT}\right)}_p=K$
Further, $T\propto V$ $T=KV$
Or ${\left(\frac{dT}{dV}\right)}_p=K$
Further, $\frac{V}{T}=K$
$\frac{1}{T}.V=K$
Differentiating w.r.t. $V$
${\left(\frac{1}{T}-\frac{V}{T^2}\right)}_p=0$