Question

According to Bohr's theory angular momentum of an electron in $6^{\text{th }}$ orbit is

• A. $2.5\frac{h}{\pi }$
• B. $6\frac{h}{\pi }$
• C. $3\frac{h}{\pi }$
• D. $\frac{2.5h}{2\pi }$

Answer 1

Answer: (C)

$mvr=\frac{nh}{2\pi }$
( $n=$ number of shell)
Angular momentum
for $6^{\text{th }}\text{ shell }=\frac{6h}{2\pi }=\frac{3h}{\pi }$