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Chemistry
According to Bohr's theory angular momentum of an electron in 6 text th orbit is
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Q. According to Bohr's theory angular momentum of an electron in $6^{\text {th }}$ orbit is
Structure of Atom
A
$2.5 \frac{ h }{\pi}$
B
$6 \frac{ h }{\pi}$
C
$3 \frac{ h }{\pi}$
D
$\frac{2.5 h}{2 \pi}$
Solution:
$mvr =\frac{ nh }{2 \pi}$
( $n=$ number of shell)
Angular momentum
for $6^{\text {th }} \text { shell }=\frac{6 h}{2 \pi}=\frac{3 h}{\pi}$